j^2-3j-4=0

Solution for j^2-3j-4=0 equation:

Simplifying
j2 + -3j + -4 = 0

Reorder the terms:
-4 + -3j + j2 = 0

Solving
-4 + -3j + j2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-1 + -1j)(4 + -1j) = 0

Subproblem 1
Set the factor '(-1 + -1j)' equal to zero and attempt to solve:

Simplifying
-1 + -1j = 0

Solving
-1 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1j = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1j = 0 + 1
-1j = 0 + 1

Combine like terms: 0 + 1 = 1
-1j = 1

Divide each side by '-1'.
j = -1

Simplifying
j = -1
Subproblem 2
Set the factor '(4 + -1j)' equal to zero and attempt to solve:

Simplifying
4 + -1j = 0

Solving
4 + -1j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1j = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1j = 0 + -4
-1j = 0 + -4

Combine like terms: 0 + -4 = -4
-1j = -4

Divide each side by '-1'.
j = 4

Simplifying
j = 4
Solution
j = {-1, 4}